Question:
Why electric potential in a equatorial line is zero
Answer:
Consider the above figure. In this, the equitorial line is met at point B.
Now, to move the charge +q to the equitorial point, force (F1) required is q/[4πε0(√r2 + l2)]
And, to move the charge +q to the equitorial point, force (F2) required is -q/[4πε0(√r2 + l2)]
Thus, the electric potential at equitorial line is F1 - F2
That is, q/[4πε0(√r2 + l2)] - q/[4πε0(√r2 + l2)]
= 0
Thus electric potential at equitorial line is always zero.
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